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May 30th, 2012 12:00
FAST Cache Setup (2 or 4)
Hello all,
I just need to provision FAST Cache for my array (CX4-480).
I have 4 available disks that I split into two buses excluding 0_0.
Documents "EMC FAST Cache, A Detailed Review" and emc251589 are very useful, but I need advise whether I configure my mirror(s) as 2 sets of 2 disks or 1 set of 4.
What would be a better setup and why if you can answer.
I appreciate your help.
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dynamox
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May 30th, 2012 19:00
this is from the same solution you mentioned earlier:
The highest level of availability can be achieved by binding the Primary and Secondary for each RAID 1 pair are on different buses (i.e. not just different enclosures on the same bus). However this does add to the complexity of configuring FAST Cache, because the configuration would need to be done using the secure CLI. This is not considered necessary for most implementations, but is done to further reduce the chances of multiple drive failures (which are already unlikely).
dynamox
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May 30th, 2012 12:00
it will automatically create 2 x RAID1 sets
here i have 4 disks used for FAST Cache
Free contiguous group of unbound segments: 0
*******************************************************************************
Free contiguous group of unbound segments: 0
Elcade
52 Posts
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May 30th, 2012 13:00
What I'm trying to figure it out is if I should select 2 or 4 drives.
Elcade
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May 30th, 2012 13:00
I'm going to dedicate all 4.
I was confused whether to choose 2 or 4 drives from the dropdown box.
I didn't know if there are any performance considerations choosing one option or the other.
dynamox
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May 30th, 2012 13:00
by the way did you see recommendation that if you have 2 or 4 drives:
As a general rule, when configuring FAST Cache, make sure all of the drives involved are either entirely contained within enclosure 0_0 (only recommended for 2 or 4 drive FAST Cache configurations) or entirely in enclosures other than 0_0. Either of these recommended configurations will not result in unnecessary rebuilds upon array power-downs. Please see emc285141 for further information about the use of Bus 0 Enclosure 0.
dynamox
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May 30th, 2012 13:00
you mean how many drives you want to dedicate for Fast Cache ?
Elcade
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May 30th, 2012 13:00
Hello dynamox,
I have the option to select 2 or 4 disks when creating the FAST Cache.
See attached picture.
Thanks!
dynamox
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May 30th, 2012 13:00
cool, none of the drives are in DAE 0_0
Just select the number of drives and let the array do the magic. You can run "naviseccli -h getrg -messner" to see how it picked the devices. I bet you one pair will be two disks on bus 1 and the other pair on bus 3.
Elcade
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May 30th, 2012 14:00
How did you find out?
dynamox
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May 30th, 2012 14:00
arrh..sorry, you have to add all 4 drives at the same time.
dynamox
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May 30th, 2012 14:00
i guess to ensure that raid1 set is spread over two buses you can select to add 2 drives first and manually add one drive from bus 1 and bus 3. Hit ok and let it build the pair. Then repeat the steps with the other 2 drives but this time add drive from bus 3 firsta and then the one from bus 1.
Message was edited by: dynamox
dynamox
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May 30th, 2012 14:00
in order to increase Fast Cache you have to destroy existing Fast Cache configuration and reconfigure it from scratch with additional disks. I am trying that right now, i want to see how my selection of disks in Unisphere will reflect the actual r1 pairing.
dynamox
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May 30th, 2012 15:00
i can't figure out in Unisphere how to manualy select 4 drives to be used for Fast Cache and control which drive is primary and secondary, so i just did it from the command line:
naviseccli -h cache -fast -create -disks 0_0_7 0_0_4 0_0_5 0_0_6 -mode rw -rtype r_1
in your case if you want to select primary and secondary on different buses you would:
naviseccli -h cache -fast -create -disks 1_1_x 3_1_x 3_1_x 1_1_x -mode rw -rtype r_1
i put "x" where the drive number is supposed to be as i can't tell what it is from your screenshot.
Elcade
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May 30th, 2012 18:00
Do you think is better to split the mirrors in buses rather than a mirror per bus?
In other words, having:
1_1_13
3_1_13
1_1_14
3_1_14
is better than
1_1_13
1_1_14
3_1_13
3_1_14
or the end result is irrelevant?
Elcade
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May 31st, 2012 07:00
You are absolutely right!
Thank you very much from your time and help.
Manuel.