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April 1st, 2025 19:45
Data Domain fastcopy
Hi,
I'm wondering what is the procedure to stop a fastcopy mounted on a mtree (eventually with storage-unit created on it).
From what I've understood, just delete the mtree - or the storage-unit will be enough.
Is it correct?
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bbeckers1
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May 9th, 2025 16:10
what do you mean with fastcopy mounted on a mtree? fastcopy is a way to actually make a copy of the source data to be able to do something with the data without touching nor changing the original data. it takes however an automatic snapshot (with very short retention) of the destination before overwriting to be able to undo, as the fastcopy overwrites the destination, if I recall correctly.
So what is it that you want to be able to do? as the copy is a mtree of its own (or even turned into a storage-unit if so required), that as long as it is un-altered points to the same underlying data blocks as the source data, but it is a separate entity.
mario_kart1
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May 9th, 2025 16:34
Hi,
as I have a storage background I was applying the same concept, indeed to remove the fast copy (let's call it snap) mount (mtree), it's enough delete the mtree (via cli)
BR,
MC
bbeckers1
2 Intern
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191 Posts
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May 9th, 2025 19:05
@mario_kart1 then it might make sense to dive deeper into the specifics of data domain and what it does and how it calls things, to make sure you get the concepts right (or at least better), this as it also has the concept of snapshots (which it for example also uses when performing MTREE replication).